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A cube $x^3$ has 3 components, the sides a, b, c (all equivalent to x):
a thinks: my change ($da$) is combined with other constant sides to get $da \times b \times c$
b and c think the same about themselves
each change happens separately with no “crosstalk” between $da$, $db$, and $dc$.
every side is identical ($a = b = c = x$)
changes are the same ($da = db = dc = dx$)
so $(dx \times x \times x) + (dx \times x \times x) + (dx \times x \times x) = x^2 \times dx + x^2 \times dx + x^2 \times dx = 3x^2 \times dx$
$x^3$ has 3 identical perspectives
When the system changes, all 3 perspectives contribute identically. Therefore, the derivative will be 3 × something.
The “something” is the change in one side (dx) multiplied by the remaining sides (x × x).
$$
\begin{equation} \int x^2 \end{equation}
$$
just imagine that incoming change is being split 3 ways:
$x^2 = \frac{x^2}{3} + \frac{x^2}{3} + \frac{x^2}{3} = \frac{1}{3} 3x^2$
now we have 3 plates (each 1/3 of the original size) and we can integrate a smaller cube.
Why many different answers for integrals? Because many different possible functions. If $f’(x) = 4$, that only shows the change for each additional step, but the starting conditions could be different (the constant $+c$).
Derivative definition:
$f(x) = 4x$ is a relationship, an increase in x by 1 raises the result by 4. The steps:
So for $f(x) = 4x$ we have $f(x + dx) - f(x) = 4(x + dx) - 4(x) = 4dx$.
This can be expressed as a ratio:
Put together:
$\frac{df}{dx} = \frac{4dx}{dx} = 4$